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Copyright © 2001-2004 Nicolai M. Josuttis
Distributed under the Boost Software License, Version 1.0.
(See accompanying file LICENSE_1_0.txt
or copy at
http://www.boost.org/LICENSE_1_0.txt)
Table of Contents
The C++ Standard Template Library STL as part of the C++ Standard Library provides a framework for processing algorithms on different kind of containers. However, ordinary arrays don't provide the interface of STL containers (although, they provide the iterator interface of STL containers).
As replacement for ordinary arrays, the STL provides class
std::vector
. However,
std::vector<>
provides
the semantics of dynamic arrays. Thus, it manages data to be able
to change the number of elements. This results in some overhead in
case only arrays with static size are needed.
In his book, Generic Programming and the
STL, Matthew H. Austern introduces a useful wrapper
class for ordinary arrays with static size, called
block
. It is safer and has no worse performance than
ordinary arrays. In The C++ Programming
Language, 3rd edition, Bjarne Stroustrup introduces a
similar class, called c_array
, which I (Nicolai Josuttis) present
slightly modified in my book The C++ Standard Library -
A Tutorial and Reference, called
carray
. This is the essence of these approaches
spiced with many feedback from boost.
After considering different names, we decided to name this
class simply array
.
Note that this class is suggested to be part of the next Technical Report, which will extend the C++ Standard (see http://std.dkuug.dk/jtc1/sc22/wg21/docs/papers/2003/n1548.htm).
Update: std::array
is (as of C++11) part of the C++ standard.
The differences between boost::array
and std::array
are minimal.
If you are using C++11, you should consider using std::array
instead of boost::array
.
Class array
fulfills most
but not all of the requirements of "reversible containers" (see
Section 23.1, [lib.container.requirements] of the C++
Standard). The reasons array is not an reversible STL container is
because:
swap
() has no constant complexity.size
() is always constant, based on the second template argument of the type.
It doesn't fulfill the requirements of a "sequence" (see Section 23.1.1, [lib.sequence.reqmts] of the C++ Standard), except that:
front
() and back
() are provided.operator[]
and at
() are provided.
Last revised: June 14, 2012 at 17:01:03 +0100 |