std::generate_n
From cppreference.com
Defined in header <algorithm>
|
||
template< class OutputIterator, class Size, class Generator >
void generate_n( OutputIterator first, Size count, Generator g ); |
(until C++11) (since C++11) |
|
Assigns values, generated by given function object g, to the first count elements in the range beginning at first, if count>0. Does nothing otherwise.
Contents |
[edit] Parameters
first | - | the beginning of the range of elements to generate | |||||||||
count | - | number of the elements to generate | |||||||||
g | - | generator function object that will be called. The signature of the function should be equivalent to the following:
The type Ret must be such that an object of type OutputIterator can be dereferenced and assigned a value of type Ret. |
[edit] Return value
(none) (until C++11)
Iterator one past the last element assigned if count>0, first otherwise. (since C++11)
[edit] Complexity
Exactly count invocations of g() and assignments, for count>0.
[edit] Possible implementation
template< class OutputIterator, class Size, class Generator > OutputIterator generate_n( OutputIterator first, Size count, Generator g ) { for( Size i = 0; i < count; i++ ) { *first++ = g(); } return first; } |
[edit] Example
The following code fills an array of integers with random numbers.
#include <cstddef> #include <cstdlib> #include <iostream> #include <iterator> #include <algorithm> int main() { const std::size_t N = 5; int ar[N]; std::generate_n(ar, N, std::rand); // Using the C function rand() std::cout << "ar: "; std::copy(ar, ar+N, std::ostream_iterator<int>(std::cout, " ")); std::cout << "\n"; }
Output:
52894 15984720 41513563 41346135 51451456
[edit] See also
assigns a value to a number of elements (function template) |
|
saves the result of a function in a range (function template) |